logy-1(8x-x^2)=2

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Solution for logy-1(8x-x^2)=2 equation:


Simplifying
logy + -1(8x + -1x2) = 2
gloy + (8x * -1 + -1x2 * -1) = 2
gloy + (-8x + 1x2) = 2

Solving
gloy + -8x + 1x2 = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '8x' to each side of the equation.
gloy + -8x + 8x + 1x2 = 2 + 8x

Combine like terms: -8x + 8x = 0
gloy + 0 + 1x2 = 2 + 8x
gloy + 1x2 = 2 + 8x

Add '-1x2' to each side of the equation.
gloy + 1x2 + -1x2 = 2 + 8x + -1x2

Combine like terms: 1x2 + -1x2 = 0
gloy + 0 = 2 + 8x + -1x2
gloy = 2 + 8x + -1x2

Divide each side by 'loy'.
g = 2l-1o-1y-1 + 8l-1o-1xy-1 + -1l-1o-1x2y-1

Simplifying
g = 2l-1o-1y-1 + 8l-1o-1xy-1 + -1l-1o-1x2y-1

Reorder the terms:
g = 8l-1o-1xy-1 + -1l-1o-1x2y-1 + 2l-1o-1y-1

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